Linking against older symbol version in a .so file
I found the following working solution. First create file memcpy.c:
#include <string.h>
/* some systems do not have newest memcpy@@GLIBC_2.14 - stay with old good one */
asm (".symver memcpy, memcpy@GLIBC_2.2.5");
void *__wrap_memcpy(void *dest, const void *src, size_t n)
{
return memcpy(dest, src, n);
}
No additional CFLAGS needed to compile this file. Then link your program with -Wl,--wrap=memcpy.
I had a similar problem. Trying to install some oracle components on RHEL 7.1, I got this:
$ gcc -o /some/oracle/bin/foo .... -L/some/oracle/lib ...
/some/oracle/lib/libfoo.so: undefined reference to `memcpy@GLIBC_2.14'
It seems that (my) RHEL's glibc only defines memcpy@GLIBC_2.2.5:
$ readelf -Ws /usr/lib/x86_64-redhat-linux6E/lib64/libc_real.so | fgrep memcpy@
367: 000000000001bfe0 16 FUNC GLOBAL DEFAULT 8 memcpy@@GLIBC_2.2.5
1166: 0000000000019250 16 FUNC WEAK DEFAULT 8 wmemcpy@@GLIBC_2.2.5
So, I managed to get around this, by first creating a memcpy.c file without wrapping, as follows:
#include <string.h>
asm (".symver old_memcpy, memcpy@GLIBC_2.2.5"); // hook old_memcpy as [email protected]
void *old_memcpy(void *, const void *, size_t );
void *memcpy(void *dest, const void *src, size_t n) // then export memcpy
{
return old_memcpy(dest, src, n);
}
and a memcpy.map file that exports our memcpy as memcpy@GLIBC_2.14:
GLIBC_2.14 {
memcpy;
};
I then compiled my own memcpy.c into a shared lib like this:
$ gcc -shared -fPIC -c memcpy.c
$ gcc -shared -fPIC -Wl,--version-script memcpy.map -o libmemcpy-2.14.so memcpy.o -lc
, moved libmemcpy-2.14.so into /some/oracle/lib (pointed to by -L arguments in my linking), and linked again by
$ gcc -o /some/oracle/bin/foo .... -L/some/oracle/lib ... /some/oracle/lib/libmemcpy-2.14.so -lfoo ...
(which compiled without errors) and verified it by:
$ ldd /some/oracle/bin/foo
linux-vdso.so.1 => (0x00007fff9f3fe000)
/some/oracle/lib/libmemcpy-2.14.so (0x00007f963a63e000)
libdl.so.2 => /lib64/libdl.so.2 (0x00007f963a428000)
libpthread.so.0 => /lib64/libpthread.so.0 (0x00007f963a20c000)
librt.so.1 => /lib64/librt.so.1 (0x00007f963a003000)
libc.so.6 => /lib64/libc.so.6 (0x00007f9639c42000)
/lib64/ld-linux-x86-64.so.2 (0x00007f963aa5b000)
This worked for me. I hope it does it for you, too.
I had a similar issue. A third party library we use needs the old memcpy@GLIBC_2.2.5
. My solution is an extended approach @anight posted.
I also warp the memcpy
command, but i had to use a slightly different approach, since the solution @anight posted did not work for me.
memcpy_wrap.c:
#include <stddef.h>
#include <string.h>
asm (".symver wrap_memcpy, memcpy@GLIBC_2.2.5");
void *wrap_memcpy(void *dest, const void *src, size_t n) {
return memcpy(dest, src, n);
}
memcpy_wrap.map:
GLIBC_2.2.5 {
memcpy;
};
Build the wrapper:
gcc -c memcpy_wrap.c -o memcpy_wrap.o
Now finally when linking the program add
-Wl,--version-script memcpy_wrap.map
memcpy_wrap.o
so that you will end up with something like:
g++ <some flags> -Wl,--version-script memcpy_wrap.map <some .o files> memcpy_wrap.o <some libs>
Just link memcpy statically - pull memcpy.o out of libc.a ar x /path/to/libc.a memcpy.o
(whatever version - memcpy is pretty much a standalone function) and include it in your final link. Note that static linking may complicate licensing issues if your project is distributed to the public and not open-source.
Alternatively, you could simply implement memcpy yourself, though the hand-tuned assembly version in glibc is likely to be more efficient
Note that memcpy@GLIBC_2.2.5 is mapped to memmove (old versions of memcpy consistently copied in a predictable direction, which led to it sometimes being misused when memmove should have been used), and this is the only reason for the version bump - you could simply replace memcpy with memmove in your code for this specific case.
Or you could go to static linking, or you could ensure that all systems on your network have the same or better version than your build machine.