linq query to return distinct field values from a list of objects

objList.Select(o=>o.typeId).Distinct()

Assuming you want the full object, but only want to deal with distinctness by typeID, there's nothing built into LINQ to make this easy. (If you just want the typeID values, it's easy - project to that with Select and then use the normal Distinct call.)

In MoreLINQ we have the DistinctBy operator which you could use:

var distinct = list.DistinctBy(x => x.typeID);

This only works for LINQ to Objects though.

You can use a grouping or a lookup, it's just somewhat annoying and inefficient:

var distinct = list.GroupBy(x => x.typeID, (key, group) => group.First());

If just want to user pure Linq, you can use groupby:

List<obj> distinct =
  objs.GroupBy(car => car.typeID).Select(g => g.First()).ToList();

If you want a method to be used all across the app, similar to what MoreLinq does:

public static IEnumerable<TSource> DistinctBy<TSource, TKey>
    (this IEnumerable<TSource> source, Func<TSource, TKey> keySelector)
{
    HashSet<TKey> seenKeys = new HashSet<TKey>();
    foreach (TSource element in source)
    {
        if (!seenKeys.Contains(keySelector(element)))
        {
            seenKeys.Add(keySelector(element));
            yield return element;
        }
    }
}

Using this method to find the distinct values using just the Id property, you could use:

var query = objs.DistinctBy(p => p.TypeId);

you can use multiple properties:

var query = objs.DistinctBy(p => new { p.TypeId, p.Name });