List comprehension in R

Something like this?

l <- 1:1000
sum(l[l %% 3 == 0 | l %% 5 == 0])

And, (kind of) the for-comprehension of scala:

for(i in {x <- 1:100;x[x%%2 == 0]})print(i)

Yes, list comprehension is possible in R:

sum((1:1000)[(1:1000 %% 3) == 0 | (1:1000 %% 5) == 0])