Apple - Listing all the groups to which a user belongs in macOS
Try the command given below.
id -Gn [user]
On my Mac, the output from id -Gn davidanderson
is given below.
staff everyone localaccounts _appserverusr admin _appserveradm _lpadmin _appstore _lpoperator _developer _analyticsusers com.apple.access_ftp com.apple.access_screensharing com.apple.access_ssh 2 1
The delimiter could be changed from a space to a comma by entering the following.
groups="$(id -Gn davidanderson)"
groups="${groups// /,}"
echo "$groups"
Here, the output would be as follows.
staff,everyone,localaccounts,_appserverusr,admin,_appserveradm,_lpadmin,_appstore,_lpoperator,_developer,_analyticsusers,com.apple.access_ftp,com.apple.access_screensharing,com.apple.access_ssh,2,1
I am using High Sierra, macOs 10.13.4 and a bash shell.
To list all the groups to which a user belongs, type:
id [username]
[username]
argument is optional. By default, the logged in user is assumed. The output will include the numeric user id uid
, and the list of all the groups along with their group id gid
, of which the user is member of. The first group in the output is the user's primary group.
To list just the group names type:
id -Gn [username]
To list just the group numbers type:
id -G [username]