Look for the GCD (greatest common divisor) of more than 2 integers?

There is a more elegant way to do this :

// Recursive function to compute gcd (euclidian method)
function gcd ($a, $b) {
    return $b ? gcd($b, $a % $b) : $a;
}
// Then reduce any list of integer
echo array_reduce(array(42, 56, 28), 'gcd'); // === 14

If you want to work with floating points, use approximation :

function fgcd ($a, $b) {
    return $b > .01 ? fgcd($b, fmod($a, $b)) : $a; // using fmod
}
echo array_reduce(array(2.468, 3.7, 6.1699), 'fgcd'); // ~= 1.232

You can use a closure in PHP 5.3 :

$gcd = function ($a, $b) use (&$gcd) { return $b ? $gcd($b, $a % $b) : $a; };

Had to do a bit of digging, but this is what I found.

The gcd of three numbers can be computed as gcd(a, b, c) = gcd(gcd(a, b), c), or in some different way by applying commutativity and associativity. This can be extended to any number of numbers.

You could use something like the following:

function multiGCD($nums)
{
    $gcd = getGCDBetween($nums[0], $nums[1]);

    for ($i = 2; $i < count($nums); $i++) { $gcd = getGCDBetween($gcd, $nums[$i]); }

    return $gcd;
}

You can try

function gcd($a, $b) {
    if ($a == 0 || $b == 0)
        return abs(max(abs($a), abs($b)));
    $r = $a % $b;
    return ($r != 0) ? gcd($b, $r) : abs($b);
}

function gcd_array($array, $a = 0) {
    $b = array_pop($array);
    return ($b === null) ? (int) $a : gcd_array($array, gcd($a, $b));
}

echo gcd_array(array(50, 100, 150, 200, 400, 800, 1000)); // output 50