max subarrays sum that are equal and their length is less than K code example

Example: Find maximum length sub-array having equal number of 0’s and 1’s

def findMaxLenSublist(A):
 
    # create an empty dictionary to store the ending index of the first
    # sublist having some sum
    dict = {}
 
    # insert `(0, -1)` pair into the set to handle the case when a
    # sublist with zero-sum starts from index 0
    dict[0] = -1
 
    # `length` stores the maximum length of sublist with zero-sum
    length = 0
 
    # stores ending index of the maximum length sublist having zero-sum
    ending_index = -1
 
    sum = 0
 
    # Traverse through the given list
    for i in range(len(A)):
 
        # sum of elements so far (replace 0 with -1)
        sum += -1 if (A[i] == 0) else 1
 
        # if the sum is seen before
        if sum in dict:
 
            # update length and ending index of maximum length
            # sublist having zero-sum
            if length < i - dict.get(sum):
                length = i - dict.get(sum)
                ending_index = i
 
        # if the sum is seen for the first time, insert the sum with its
        # index into the dictionary
        else:
            dict[sum] = i
 
    # print the sublist if present
    if ending_index != -1:
        print((ending_index - length + 1, ending_index))
    else:
        print("No sublist exists")