merge and sort code example

Example 1: merge sort algo

def mergeSort(arr): 
    if len(arr) >1: 
        mid = len(arr)//2 # Finding the mid of the array 
        L = arr[:mid] # Dividing the array elements  
        R = arr[mid:] # into 2 halves 
  
        mergeSort(L) # Sorting the first half 
        mergeSort(R) # Sorting the second half 
  
        i = j = k = 0
          
        # Copy data to temp arrays L[] and R[] 
        while i < len(L) and j < len(R): 
            if L[i] < R[j]: 
                arr[k] = L[i] 
                i+= 1
            else: 
                arr[k] = R[j] 
                j+= 1
            k+= 1
          
        # Checking if any element was left 
        while i < len(L): 
            arr[k] = L[i] 
            i+= 1
            k+= 1
          
        while j < len(R): 
            arr[k] = R[j] 
            j+= 1
            k+= 1
  
# Code to print the list 
def printList(arr): 
    for i in range(len(arr)):         
        print(arr[i], end =" ") 
    print() 
  
# driver code to test the above code 
if __name__ == '__main__': 
    arr = [12, 11, 13, 5, 6, 7]  
    print ("Given array is", end ="\n")  
    printList(arr) 
    mergeSort(arr) 
    print("Sorted array is: ", end ="\n") 
    printList(arr)

Example 2: merge sort

# Python3 recursive merge sort algorithm -> O(n*log(n))
def merge_sort(A):
    def merge(l, r):
        i = j = 0
        n = []  # merging container
        while i < len(l) or j < len(r):

            # if no more elements to the right,
            # add remaining left elements
            if i == len(l):
                n.extend(r[j:])
                break

            # if no more elements to the left,
            # add remaining right elements
            if j == len(r):
                n.extend(l[i:])
                break

            # if elements left on both sides,
            # add smaller element
            a, b = l[i], r[j]
            if a < b:
                n.append(a)
                i += 1
            else:
                n.append(b)
                j += 1

        return n

    # divide list down to single-elements
    s = len(A)
    if s > 1:
        s //= 2
        l = merge_sort(A[:s])  # split left
        r = merge_sort(A[s:])  # split right
        return merge(l, r)  # merge sides in order
    else:
        return A