Mongo order by length of array
I use $project
for this:
db.test.aggregate([
{
$project : { answers_count: {$size: { "$ifNull": [ "$answers", [] ] } } }
},
{
$sort: {"answers_count":1}
}
])
It also allows to include documents with empty answers.
But also has a disadvantage (or sometimes advantage): you should manually add all needed fields in $project
step.
I thought you might be able to use $size
, but that's only to find arrays of a certain size, not ordering.
From the mongo documentation: http://www.mongodb.org/display/DOCS/Advanced+Queries#AdvancedQueries-%24size
You cannot use $size to find a range of sizes (for example: arrays with more than 1 element). If you need to query for a range, create an extra size field that you increment when you add elements. Indexes cannot be used for the $size portion of a query, although if other query expressions are included indexes may be used to search for matches on that portion of the query expression.
Looks like you can probably fairly easily do this with the new aggregation framework, edit: which isn't out yet. http://www.mongodb.org/display/DOCS/Aggregation+Framework
Update Now the Aggregation Framework is out...
> db.test.aggregate([
{$unwind: "$answers"},
{$group: {_id:"$_id", answers: {$push:"$answers"}, size: {$sum:1}}},
{$sort:{size:1}}]);
{
"result" : [
{
"_id" : ObjectId("5053b4547d820880c3469365"),
"answers" : [
{
"content" : "answer1"
},
{
"content" : "2nd answer"
}
],
"size" : 2
},
{
"_id" : ObjectId("5053b46d7d820880c3469366"),
"answers" : [
{
"content" : "answer1"
},
{
"content" : "2nd answer"
},
{
"content" : "The third answer"
}
],
"size" : 3
}
],
"ok" : 1
}
you can use mongodb aggregation stage $addFields
which will add extra field to store count and then followed by $sort
stage.
db.test.aggregate([
{
$addFields: { answers_count: {$size: { "$ifNull": [ "$answers", [] ] } } }
},
{
$sort: {"answers_count":1}
}
])