Multidimensional Euclidean Distance in Python

Use either

numpy.sqrt(numpy.sum((A - B)**2))

or more simply

numpy.linalg.norm(A - B)

Perhaps scipy.spatial.distance.euclidean?

Examples

>>> from scipy.spatial import distance
>>> distance.euclidean([1, 0, 0], [0, 1, 0])
1.4142135623730951
>>> distance.euclidean([1, 1, 0], [0, 1, 0])
1.0