MySQL 5 left join unknown column
You can only refer the tables previously joined with the JOIN
clause in the ON
clause.
SELECT *
FROM email e
JOIN event_email ee
ON ee.email_id = e.email_id
LEFT JOIN
member m
ON m.email = e.email
This can be illustrated better if I put the parentheses around the ANSI JOINS
in your original query:
SELECT *
FROM email e,
(
event_email ee
LEFT JOIN
member m
ON m.email = e.email
)
WHERE ee.email_id = e.email_id
As you can see, there is no source for e.email
inside the parentheses: that's why it could not be resolved.
From MySQL documentation page
Previously, the comma operator (,) and JOIN both had the same precedence, so the join expression t1, t2 JOIN t3 was interpreted as ((t1, t2) JOIN t3). Now JOIN has higher precedence, so the expression is interpreted as (t1, (t2 JOIN t3)). This change affects statements that use an ON clause, because that clause can refer only to columns in the operands of the join, and the change in precedence changes interpretation of what those operands are.
Example:
CREATE TABLE t1 (i1 INT, j1 INT);
CREATE TABLE t2 (i2 INT, j2 INT);
CREATE TABLE t3 (i3 INT, j3 INT);
SELECT * FROM t1, t2 JOIN t3 ON (t1.i1 = t3.i3);
Previously, the SELECT was legal due to the implicit grouping of t1,t2 as (t1,t2). Now the JOIN takes precedence, so the operands for the ON clause are t2 and t3. Because t1.i1 is not a column in either of the operands, the result is an Unknown column 't1.i1' in 'on clause' error. To allow the join to be processed, group the first two tables explicitly with parentheses so that the operands for the ON clause are (t1,t2) and t3:
SELECT * FROM (t1, t2) JOIN t3 ON (t1.i1 = t3.i3);
Alternatively, avoid the use of the comma operator and use JOIN instead:
SELECT * FROM t1 JOIN t2 JOIN t3 ON (t1.i1 = t3.i3);
This change also applies to statements that mix the comma operator with INNER JOIN, CROSS JOIN, LEFT JOIN, and RIGHT JOIN, all of which now have higher precedence than the comma operator.
The answer would be to place the JOIN statement directly after the table in the FROM statement, because that is the table you are joining on:
SELECT *
FROM email e
LEFT JOIN member m on m.email=e.email,
event_email ee
WHERE ee.email_id = e.email_id