Mysql count instances of substring, then order by
SELECT (CHAR_LENGTH(str) - CHAR_LENGTH(REPLACE(str, substr, ''))) / CHAR_LENGTH(substr) AS cnt
...
ORDER BY cnt DESC
Yep, looks bloated but afaik there is no any other possible solution.
mysql> select (CHAR_LENGTH('asd') - CHAR_LENGTH(REPLACE('asd', 's', ''))) / CHAR_LENGTH('s');
+-----------------------------------------------------------------+
| (CHAR_LENGTH('asd') - CHAR_LENGTH(REPLACE('asd', 's', ''))) / CHAR_LENGTH('s') |
+-----------------------------------------------------------------+
| 1.0000 |
+-----------------------------------------------------------------+
1 row in set (0.00 sec)
mysql> select host, (CHAR_LENGTH(host) - CHAR_LENGTH(REPLACE(host, 'l', ''))) / CHAR_LENGTH('l') AS cnt from user;
+-----------+--------+
| host | cnt |
+-----------+--------+
| 127.0.0.1 | 0.0000 |
| honeypot | 0.0000 |
| honeypot | 0.0000 |
| localhost | 2.0000 |
| localhost | 2.0000 |
+-----------+--------+
5 rows in set (0.00 sec)
DELIMITER //
DROP FUNCTION IF EXISTS `subStringCount`//
CREATE FUNCTION `subStringCount` (sequence VARCHAR(1000), word VARCHAR(100)) RETURNS INT(4)
DETERMINISTIC
CONTAINS SQL
BEGIN
DECLARE counter SMALLINT UNSIGNED DEFAULT 0;
DECLARE word_length SMALLINT UNSIGNED;
SET word_length = CHAR_LENGTH(word);
WHILE (INSTR(sequence,word) != 0) DO
SET counter = counter+1;
SET sequence = SUBSTR(sequence, INSTR(sequence,word)+word_length);
END WHILE;
RETURN counter;
END //
DELIMITER ;
Which can be executed by calling:
SELECT sum(subStringCount(fieldName,'subString')) FROM `table` WHERE 1