New Array from Index Range Swift

Array functional way:

   array.enumerated().filter { $0.offset < limit }.map { $0.element }

ranged:

 array.enumerated().filter { $0.offset >= minLimit && $0.offset < maxLimit }.map { $0.element }

The advantage of this method is such implementation is safe.

#1. Using Array subscript with range

With Swift 5, when you write…

let newNumbers = numbers[0...position]

… newNumbers is not of type Array<Int> but is of type ArraySlice<Int>. That's because Array's subscript(_:​) returns an ArraySlice<Element> that, according to Apple, presents a view onto the storage of some larger array.

Besides, Swift also provides Array an initializer called init(_:​) that allows us to create a new array from a sequence (including ArraySlice).

Therefore, you can use subscript(_:​) with init(_:​) in order to get a new array from the first n elements of an array:

let array = Array(10...14) // [10, 11, 12, 13, 14]
let arraySlice = array[0..<3] // using Range
//let arraySlice = array[0...2] // using ClosedRange also works
//let arraySlice = array[..<3] // using PartialRangeUpTo also works
//let arraySlice = array[...2] // using PartialRangeThrough also works
let newArray = Array(arraySlice)
print(newArray) // prints [10, 11, 12]

---

#2. Using Array's prefix(_:) method

Swift provides a prefix(_:) method for types that conform to Collection protocol (including Array). prefix(_:) has the following declaration:

func prefix(_ maxLength: Int) -> ArraySlice<Element>

Returns a subsequence, up to maxLength in length, containing the initial elements.

Apple also states:

If the maximum length exceeds the number of elements in the collection, the result contains all the elements in the collection.

Therefore, as an alternative to the previous example, you can use the following code in order to create a new array from the first elements of another array:

let array = Array(10...14) // [10, 11, 12, 13, 14]
let arraySlice = array.prefix(3)
let newArray = Array(arraySlice)
print(newArray) // prints [10, 11, 12]

This works for me:

var test = [1, 2, 3]
var n = 2
var test2 = test[0..<n]

Your issue could be with how you're declaring your array to begin with.

EDIT:

To fix your function, you have to cast your Slice to an array:

func aFunction(numbers: Array<Int>, position: Int) -> Array<Int> {
    var newNumbers = Array(numbers[0..<position])
    return newNumbers
}

// test
aFunction([1, 2, 3], 2) // returns [1, 2]

subscript

extension Array where Element : Equatable {
  public subscript(safe bounds: Range<Int>) -> ArraySlice<Element> {
    if bounds.lowerBound > count { return [] }
    let lower = Swift.max(0, bounds.lowerBound)
    let upper = Swift.max(0, Swift.min(count, bounds.upperBound))
    return self[lower..<upper]
  }
  
  public subscript(safe lower: Int?, _ upper: Int?) -> ArraySlice<Element> {
    let lower = lower ?? 0
    let upper = upper ?? count
    if lower > upper { return [] }
    return self[safe: lower..<upper]
  }
}

returns a copy of this range clamped to the given limiting range.

var arr = [1, 2, 3]
    
arr[safe: 0..<1]    // returns [1]  assert(arr[safe: 0..<1] == [1])
arr[safe: 2..<100]  // returns [3]  assert(arr[safe: 2..<100] == [3])
arr[safe: -100..<0] // returns []   assert(arr[safe: -100..<0] == [])

arr[safe: 0, 1]     // returns [1]  assert(arr[safe: 0, 1] == [1])
arr[safe: 2, 100]   // returns [3]  assert(arr[safe: 2, 100] == [3])
arr[safe: -100, 0]  // returns []   assert(arr[safe: -100, 0] == [])