New symbol derived from [a, b]
Before someone comes with a TikZ solution...
\documentclass{article}
% \usepackage{amsmath}
\makeatletter
\newcommand*{\foo}{\mathpalette\@foo}
\newcommand*{\@foo}[2]{%
% rule thickness
\@tempdima=\fontdimen8
\ifx#1\displaystyle\textfont\else
\ifx#1\textstyle\textfont\else
\ifx#1\scriptstyle\scriptfont\else
\scriptscriptfont\fi\fi\fi 3
% spacing around the symbols 0.5ex
\@tempdimb=0.5\fontdimen5
\ifx#1\displaystyle\textfont\else
\ifx#1\textstyle\textfont\else
\ifx#1\scriptstyle\scriptfont\else
\scriptscriptfont\fi\fi\fi 2
\sbox0{\m@th\kern\@tempdimb$#1#2$\kern\@tempdimb}%
\ht0=\dimexpr\ht0+\@tempdimb\relax
\dp0=\dimexpr\dp0+\@tempdimb\relax
\lower\dimexpr\dp0+\@tempdima\relax
\hbox{%
\vrule\@width\@tempdima
\vbox{\offinterlineskip
\hb@xt@\wd0{\vrule\@height\@tempdima\@width\@tempdimb\hfil\vrule\@height\@tempdima\@width\@tempdimb}%
\box0
\hrule\@height\@tempdima
}%
\vrule\@width\@tempdima
}%
}
\makeatother
\begin{document}
$\foo{a,b}$
$\scriptstyle\foo{a,b}$
$\scriptscriptstyle\foo{a,b}$
\medskip
$\displaystyle\foo{-\frac{a}{2},\frac{a}{2}}$
$\foo{-\frac{a}{2},\frac{a}{2}}$
$\scriptstyle\foo{-\frac{a}{2},\frac{a}{2}}$
$\scriptscriptstyle\foo{-\frac{a}{2},\frac{a}{2}}$
\end{document}
The two lengths scale accordingly to the current math style: \@tempdima
is the standard rule thickness, while \@tempdimb
is basicall half ex
(the latter could be fixed without resorting to \fontdimen
).
If you uncomment amsmath
then the result will differ slightly in \scriptscriptstyle
, where you get
without amsmath
:
with amsmath
:
If your symbols don't have excessive depth (no fractions, for instance), you can get away with
\documentclass{article}
\usepackage{amsmath,array}
\makeatletter
\newcommand{\segment}[1]{%
\big\lceil\colas@segment{#1}\big\rceil
}
\newcommand{\colas@segment}[1]{%
\mspace{-4.85mu}%
\underline{\mspace{5mu}#1\vphantom{j}\mspace{5mu}}%
\mspace{-4.85mu}%
}
\makeatother
\begin{document}
\Huge
\indent\rlap{\vrule height0pt depth0.1pt width 4cm}%
$\segment{a,b}=\{ta+(1-t)b: t\in[0,1]\}$
\indent\rlap{\vrule height0pt depth0.1pt width 4cm}%
$\segment{p,q}=\{tp+(1-t)q: t\in[0,1]\}$
\end{document}