No index path for table cell being reused

In my case, this error was presented only on iPhone (not iPad) because I had placed [self.tableView beginUpdates]; and later [self.tableView endUpdates]; inside [UIView transitionWithView:duration:options:animations:compeletion];. To fix, I just removed begin/end updates, as I preferred a fading animation instead of fading plus animating cell height changes.

I have just tracked down a cause of this error message.

A UITableViewCell was being used as a normal view. Therefore its' indexPath was not set. In our case one was being returned by viewForHeaderInSection:

Hope this helps.

Chris

Return [cell contentView] instead of cell from tableView:viewForHeaderInSection:

EDIT: This somehow led to crashes on long-press gestures on UI Buttons. To fix that, I gave up and used another section with a single item as a fake section header.

I found this warning during my viewForHeaderInSection implementation.

This is my solution in Swift 2.x:

let headerView = self.tableView.dequeueReusableCellWithIdentifier("MyCell") as! MyCell
let containerView = UIView(frame:headerView.frame)
headerView.autoresizingMask = [.FlexibleWidth, .FlexibleHeight]
headerView.myLabel.text = "section title 1"
containerView.addSubview(headerView)
return containerView

This is the Swift 3 version:

let headerView = self.tableView.dequeueReusableCell(withIdentifier: "MyCell") as! MyCell
let containerView = UIView(frame:headerView.frame)
headerView.autoresizingMask = [.flexibleWidth, .flexibleHeight]
headerView.myLabel.text = "section title 1"
containerView.addSubview(headerView)
return containerView