Number of digits in exponent
You can use np.format_float_scientific
from numpy import format_float_scientific
f = 0.0000870927939438012
format_float_scientific(f, exp_digits=3) # prints '8.70927939438012e-005'
format_float_scientific(f, exp_digits=5, precision=2) #prints '8.71e-00005'
There is a no way to control that, best way is to write a function for this e.g.
def eformat(f, prec, exp_digits):
s = "%.*e"%(prec, f)
mantissa, exp = s.split('e')
# add 1 to digits as 1 is taken by sign +/-
return "%se%+0*d"%(mantissa, exp_digits+1, int(exp))
print eformat(0.0000870927939438012, 14, 3)
print eformat(1.0000870927939438012e5, 14, 3)
print eformat(1.1e123, 4, 4)
print eformat(1.1e-123, 4, 4)
Output:
8.70927939438012e-005
1.00008709279394e+005
1.1000e+0123
1.1000e-0123