Numpy slice of arbitrary dimensions

Actually, just found the answer. As stated in numpy's documentation this can be done with the slice object. In my particular case, this would do it:

idx = [slice(None)] * (myarray.ndim - 1) + [i] 
my_slice = myarray[idx]

The slice(None) is equivalent to choosing all elements in that index, and the last [i] selects a specific index for the last dimension.

There is ... or Ellipsis, which does exactly this:

slice = myarray[..., i]

Ellipsis is the python object, if you should want to use it outside the square bracket notation.

In terms of slicing an arbitrary dimension, the previous excellent answers can be extended to:

indx = [slice(None)]*myarray.ndim
indx[slice_dim] = i
sliced = myarray[indx]

This returns the slice from any dimension slice_dim - slice_dim = -1 reproduces the previous answers. For completeness - the first two lines of the above listing can be condensed to:

indx = [slice(None)]*(slice_dim) + [i] + [slice(None)]*(myarray.ndim-slice_dim-1)

though I find the previous version more readable.