Open Settings App from another App in iOS - React Native

You can access settings of the application with: Linking.openURL('app-settings:');

But I don't know (yet) how to open a specific deep-link.

2021 update use:

Linking.openSettings();

otherwise your app will be rejected due use of non-public URL scheme

I successfully opened the settings by the code below, hope it's helpful :)

Linking.canOpenURL('app-settings:').then(supported => {
  if (!supported) {
    console.log('Can\'t handle settings url');
  } else {
    return Linking.openURL('app-settings:');
  }
}).catch(err => console.error('An error occurred', err));

Reference: https://facebook.github.io/react-native//docs/linking.html

Since React Native version 0.59 this should be possible using openSettings();. This is described in the React Native Linking documentation. Although it did not work for me. When I tried quickly I saw a _reactNative.Linking.openSettings is not a function error message.

Linking.openSettings();