Order a List (C#) by many fields?

Make your object something like

public class MyObject : IComparable
{
    public string a;
    public string b;

    virtual public int CompareTo(object obj)
    {
        if (obj is MyObject)
        {
            var compareObj = (MyObject)obj;
            if (this.a.CompareTo(compareObj.a) == 0)
            {
                // compare second value
                return this.b.CompareTo(compareObj.b);
            }
            return this.a.CompareTo(compareObj.b);
        }
        else
        {
            throw new ArgumentException("Object is not a MyObject ");
        }
    }
}

also note that the returns for CompareTo :

http://msdn.microsoft.com/en-us/library/system.icomparable.compareto.aspx

Then, if you have a List of MyObject, call .Sort() ie

var objList = new List<MyObject>();
objList.Sort();

Use ThenBy:

var orderedCustomers = Customer.OrderBy(c => c.LastName).ThenBy(c => c.FirstName)

See MSDN: http://msdn.microsoft.com/en-us/library/bb549422.aspx

Yes, you can do it by specifying the comparison method. The advantage is the sorted object don't have to be IComparable

   aListOfObjects.Sort((x, y) =>
   {
       int result = x.A.CompareTo(y.A);
       return result != 0 ? result : x.B.CompareTo(y.B);
   });