Overriding a JavaScript function while referencing the original
You can override a function using a construct like:
function override(f, g) {
return function() {
return g(f);
};
}
For example:
a = override(a, function(original_a) {
if (condition) { new_code(); original_a(); }
else { original_a(); other_new_code(); }
});
Edit: Fixed a typo.
You could do something like this:
var a = (function() {
var original_a = a;
if (condition) {
return function() {
new_code();
original_a();
}
} else {
return function() {
original_a();
other_new_code();
}
}
})();
Declaring original_a
inside an anonymous function keeps it from cluttering the global namespace, but it's available in the inner functions.
Like Nerdmaster mentioned in the comments, be sure to include the ()
at the end. You want to call the outer function and store the result (one of the two inner functions) in a
, not store the outer function itself in a
.
Thanks guys the proxy pattern really helped.....Actually I wanted to call a global function foo.. In certain pages i need do to some checks. So I did the following.
//Saving the original func
var org_foo = window.foo;
//Assigning proxy fucnc
window.foo = function(args){
//Performing checks
if(checkCondition(args)){
//Calling original funcs
org_foo(args);
}
};
Thnx this really helped me out
The Proxy pattern might help you:
(function() {
// log all calls to setArray
var proxied = jQuery.fn.setArray;
jQuery.fn.setArray = function() {
console.log( this, arguments );
return proxied.apply( this, arguments );
};
})();
The above wraps its code in a function to hide the "proxied"-variable. It saves jQuery's setArray-method in a closure and overwrites it. The proxy then logs all calls to the method and delegates the call to the original. Using apply(this, arguments) guarantees that the caller won't be able to notice the difference between the original and the proxied method.