Pandas still getting SettingWithCopyWarning even after using .loc
Note: As of pandas version 0.24, is_copy is deprecated and will be removed in a future version. While the private attribute _is_copy exists, the underscore indicates this attribute is not part of the public API and therefore should not be depended upon. Therefore, going forward, it seems the only proper way to silence SettingWithCopyWarning will be to do so globally:
pd.options.mode.chained_assignment = None
When complete = train.dropna() is executed, dropna might return a copy, so
out of an abundance of caution, Pandas sets complete.is_copy to a Truthy
value:
In [220]: complete.is_copy
Out[220]: <weakref at 0x7f7f0b295b38; to 'DataFrame' at 0x7f7eee6fe668>
This allows Pandas to warn you later, when complete['AgeGt15'] = complete['Age'] > 15 is executed that you may be modifying a copy which will have no effect on train. For beginners this may be a useful warning. In your case, it appears you have no intention of modifying train indirectly by modifying complete. Therefore the warning is just a meaningless annoyance in your case.
You can silence the warning by setting,
complete.is_copy = False # deprecated as of version 0.24
This is quicker than making an actual copy, and nips the SettingWithCopyWarning in the bud (at the point where _check_setitem_copy is called):
def _check_setitem_copy(self, stacklevel=4, t='setting', force=False):
if force or self.is_copy:
...
If you are really confident you know what you are doing, you can shut off the SettingWithCopyWarning globally with
pd.options.mode.chained_assignment = None # None|'warn'|'raise'
An alternative way to silence the warning is to make a new copy:
complete = complete.copy()
However, you may not want to do this if the DataFrame is large, since copying
can take a significant amount of time and memory, and it is
completely pointless (except for the sake of silencing a warning) if you know complete is already a copy.
I resolve it by creating copy of dataframe:
complete = train.copy()