Parse file name and path from full path
I do a lot of ETL work and I was looking for a function that I could use and qub1n's solution works very good except for values without a back slash. Here is a little tweak of qub1n's solution that will handle strings without back slashes:
Create FUNCTION fnGetFileName
(
@fullpath nvarchar(260)
)
RETURNS nvarchar(260)
AS
BEGIN
IF(CHARINDEX('\', @fullpath) > 0)
SELECT @fullpath = RIGHT(@fullpath, CHARINDEX('\', REVERSE(@fullpath)) -1)
RETURN @fullpath
END
Samples:
SELECT [dbo].[fnGetFileName]('C:\Test\New Text Document.txt') --> New Text Document.txt
SELECT [dbo].[fnGetFileName]('C:\Test\Text Docs\New Text Document.txt') --> New Text Document.txt
SELECT [dbo].[fnGetFileName]('New Text Document.txt') --> New Text Document.txt
SELECT [dbo].[fnGetFileName]('\SERVER\D$\EXPORTFILES\EXPORT001.csv') --> EXPORT001.csv
Here is a LINK to SqlFiddle
Here is the simplest way
DECLARE @full_path VARCHAR(1000)
SET @full_path = '\\SERVER\D$\EXPORTFILES\EXPORT001.csv'
SELECT LEFT(@full_path, LEN(@full_path) - CHARINDEX('\', REVERSE(@full_path)) - 1),
RIGHT(@full_path, CHARINDEX('\', REVERSE(@full_path)) - 1)
Answer based on comment by Stefan Steiger:
Create FUNCTION GetFileName
(
@fullpath nvarchar(260)
)
RETURNS nvarchar(260)
AS
BEGIN
DECLARE @charIndexResult int
SET @charIndexResult = CHARINDEX('\', REVERSE(@fullpath))
IF @charIndexResult = 0
RETURN NULL
RETURN RIGHT(@fullpath, @charIndexResult -1)
END
GO
Test code:
DECLARE @fn nvarchar(260)
EXEC @fn = dbo.GetFileName 'AppData\goto\image.jpg'
PRINT @fn -- prints image.jpg
EXEC @fn = dbo.GetFileName 'c:\AppData\goto\image.jpg'
PRINT @fn -- prints image.jpg
EXEC @fn = dbo.GetFileName 'image.jpg'
PRINT @fn -- prints NULL
Use this -
DECLARE @full_path VARCHAR(1000)
SET @full_path = '\\SERVER\D$\EXPORTFILES\EXPORT001.csv'
SELECT LEFT(@full_path,LEN(@full_path) - charindex('\',reverse(@full_path),1) + 1) [path],
RIGHT(@full_path, CHARINDEX('\', REVERSE(@full_path)) -1) [file_name]