Perl 6 iterate through command line arguments

So it depends on what you want to do with the files. If you want to read through them all you might want to take a look at $*ARGFILES this is an IO::CatHandle Object that batches up all the arguments and treats them as a list of files. So to print them all out you could do.

#! /usr/bin/env perl6
use v6;

for $*ARGFILES.handles -> $IO {
    $IO.path.say
}

Ok so that's a bit more convoluted than looking at @*ARGS. But what if you wanted to print the first 5 lines for each file?

#! /usr/bin/env perl6
use v6;

for $*ARGFILES.handles -> $IO {
    say $IO.lines: 5;
}

Or maybe you just want to read the contents of all the files and print them out?

#! /usr/bin/env perl6
use v6;

.say for $*ARGFILES.lines;

Hope that gives you some ideas.

For Perl6 the arguments array is @*ARGS, this gives the code:

#! /usr/bin/env perl6

use v6;

for @*ARGS -> $arg
{
    print("Arg $arg\n");
}  

So you just need to remove the .perl from your my @args = @*ARGS.perl; line.

EDIT: Updated as per Ralphs's comments