ajax all data show in database for table format without refresh in laravel code example
Example: onload fetch data using ajax laravel
<!doctype html>
<html>
<body>
<input type='text' id='search' name='search' placeholder='Enter userid 1-27'><input type='button' value='Search' id='but_search'>
<br/>
<input type='button' value='Fetch all records' id='but_fetchall'>
<table border='1' id='userTable' style='border-collapse: collapse;'>
<thead>
<tr>
<th>S.no</th>
<th>Username</th>
<th>Name</th>
<th>Email</th>
</tr>
</thead>
<tbody></tbody>
</table>
<!-- Script -->
<!-- <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> --> <!-- jQuery CDN -->
<script src="{{asset('js/jquery-3.3.1.min.js')}}"></script>
<script type='text/javascript'>
$(document).ready(function(){
$('#but_fetchall').click(function(){
fetchRecords(0);
});
$('#but_search').click(function(){
var userid = Number($('#search').val().trim());
if(userid > 0){
fetchRecords(userid);
}
});
});
function fetchRecords(id){
$.ajax({
url: 'getUsers/'+id,
type: 'get',
dataType: 'json',
success: function(response){
var len = 0;
$('#userTable tbody').empty();
if(response['data'] != null){
len = response['data'].length;
}
if(len > 0){
for(var i=0; i<len; i++){
var id = response['data'][i].id;
var username = response['data'][i].username;
var name = response['data'][i].name;
var email = response['data'][i].email;
var tr_str = "<tr>" +
"<td align='center'>" + (i+1) + "</td>" +
"<td align='center'>" + username + "</td>" +
"<td align='center'>" + name + "</td>" +
"<td align='center'>" + email + "</td>" +
"</tr>";
$("#userTable tbody").append(tr_str);
}
}else{
var tr_str = "<tr>" +
"<td align='center' colspan='4'>No record found.</td>" +
"</tr>";
$("#userTable tbody").append(tr_str);
}
}
});
}
</script>
</body>
</html>