image upload sql php code example

Example 1: image upload in php code with databases

<?php
  // Create database connection
  $db = mysqli_connect("localhost", "root", "", "image_upload");

  // Initialize message variable
  $msg = "";

  // If upload button is clicked ...
  if (isset($_POST['upload'])) {
  	// Get image name
  	$image = $_FILES['image']['name'];
  	// Get text
  	$image_text = mysqli_real_escape_string($db, $_POST['image_text']);

  	// image file directory
  	$target = "images/".basename($image);

  	$sql = "INSERT INTO images (image, image_text) VALUES ('$image', '$image_text')";
  	// execute query
  	mysqli_query($db, $sql);

  	if (move_uploaded_file($_FILES['image']['tmp_name'], $target)) {
  		$msg = "Image uploaded successfully";
  	}else{
  		$msg = "Failed to upload image";
  	}
  }
  $result = mysqli_query($db, "SELECT * FROM images");
?>
<!DOCTYPE html>
<html>
<head>
<title>Image Upload</title>
<style type="text/css">
   #content{
   	width: 50%;
   	margin: 20px auto;
   	border: 1px solid #cbcbcb;
   }
   form{
   	width: 50%;
   	margin: 20px auto;
   }
   form div{
   	margin-top: 5px;
   }
   #img_div{
   	width: 80%;
   	padding: 5px;
   	margin: 15px auto;
   	border: 1px solid #cbcbcb;
   }
   #img_div:after{
   	content: "";
   	display: block;
   	clear: both;
   }
   img{
   	float: left;
   	margin: 5px;
   	width: 300px;
   	height: 140px;
   }
</style>
</head>
<body>
<div id="content">
  <?php
    while ($row = mysqli_fetch_array($result)) {
      echo "<div id='img_div'>";
      	echo "<img src='images/".$row['image']."' >";
      	echo "<p>".$row['image_text']."</p>";
      echo "</div>";
    }
  ?>
  <form method="POST" action="index.php" enctype="multipart/form-data">
  	<input type="hidden" name="size" value="1000000">
  	<div>
  	  <input type="file" name="image">
  	</div>
  	<div>
      <textarea 
      	id="text" 
      	cols="40" 
      	rows="4" 
      	name="image_text" 
      	placeholder="Say something about this image..."></textarea>
  	</div>
  	<div>
  		<button type="submit" name="upload">POST</button>
  	</div>
  </form>
</div>
</body>
</html>

Example 2: how to place the path of an uploaded image in a database on an html file input

<?php
include("config.php");

if(isset($_POST['but_upload'])){
 
  $name = $_FILES['file']['name'];
  $target_dir = "upload/";
  $target_file = $target_dir . basename($_FILES["file"]["name"]);

  // Select file type
  $imageFileType = strtolower(pathinfo($target_file,PATHINFO_EXTENSION));

  // Valid file extensions
  $extensions_arr = array("jpg","jpeg","png","gif");

  // Check extension
  if( in_array($imageFileType,$extensions_arr) ){
 
    // Convert to base64 
    $image_base64 = base64_encode(file_get_contents($_FILES['file']['tmp_name']) );
    $image = 'data:image/'.$imageFileType.';base64,'.$image_base64;
    // Insert record
    $query = "insert into images(image) values('".$image."')";
    mysqli_query($con,$query);
  
    // Upload file
    move_uploaded_file($_FILES['file']['tmp_name'],$target_dir.$name);
  }
 
}
?>

<form method="post" action="" enctype='multipart/form-data'>
  <input type='file' name='file' />
  <input type='submit' value='Save name' name='but_upload'>
</form>

Example 3: how to upload image in php

<!DOCTYPE html><html><body><form action="upload.php" method="post"
enctype="multipart/form-data">    Select image to upload:    <input type="file" name="fileToUpload" id="fileToUpload">    <input type="submit" value="Upload Image" name="submit">
</form></body></html>

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