PHP's json_encode does not escape all JSON control characters

function escapeJsonString($value) {
    # list from www.json.org: (\b backspace, \f formfeed)    
    $escapers =     array("\\",     "/",   "\"",  "\n",  "\r",  "\t", "\x08", "\x0c");
    $replacements = array("\\\\", "\\/", "\\\"", "\\n", "\\r", "\\t",  "\\f",  "\\b");
    $result = str_replace($escapers, $replacements, $value);
    return $result;
  }

I'm using the above function which escapes a backslash (must be first in the arrays) and should deal with formfeeds and backspaces (I don't think \f and \b are supported in PHP).

D'oh - you need to double-encode: JSON.parse is expecting a string of course:

<script type="text/javascript">

JSON.parse(<?php echo json_encode($s) ?>);

</script>

I still haven't figured out any solution without str_replace..

Try this code.

$json_encoded_string = json_encode(...);
$json_encoded_string = str_replace("\r", '\r', $json_encoded_string);
$json_encoded_string = str_replace("\n", '\n', $json_encoded_string);

Hope that helps...