print all substrings of a string using recursion code example
Example 1: find all occurrences of a substring in a string c++
#include <string>
#include <iostream>
using namespace std;
int main()
{
string s("hello hello");
int count = 0;
size_t nPos = s.find("hello", 0);
while(nPos != string::npos)
{
count++;
nPos = s.find("hello", nPos + 1);
}
cout << count;
};
Example 2: loop and save letters in a string java
public static void main(String[] args){
Scanner input = new Scanner(System.in);
System.out.print("Enter phone number: ");
String number = input.nextLine();
String phone ="";
for (int i = 0; i < number.length(); i++){
if (Character.isLetter(number.charAt(i)))
phone = getNumber(Character.toUpperCase(number.charAt(i)));
else
number.charAt(i);
}
System.out.println("Your number is " + phone);
}
public static int getNumber(char uppercaseLetter){
if (uppercaseLetter >= 'W' && uppercaseLetter <= 'Z')
return 9;
else if (uppercaseLetter >= 'T' && uppercaseLetter < 'W')
return 8;
else if (uppercaseLetter >= 'P' && uppercaseLetter < 'T')
return 7;
else if (uppercaseLetter >= 'M' && uppercaseLetter < 'P')
return 6;
else if (uppercaseLetter >= 'J' && uppercaseLetter < 'M')
return 5;
else if (uppercaseLetter >= 'G' && uppercaseLetter < 'J')
return 4;
else if (uppercaseLetter >= 'D' && uppercaseLetter < 'G')
return 3;
else
return 2;
}
}