Print the Greek national anthem

Jelly, 180 174 163 bytes

60r26;“WSNME‘ȷ_Ọ;“ ¶.',!”“¢Iç÷ṀDė3H⁷'UBV“ñẸḣY]ṭżẸ-dƒjṭ{^ṣ8ḞkƊK“ẈḊbƝÑk?Æ.)Aɱ3ẎƬṠ⁵ʂ÷Gẏp⁴ṇ1ẸR ¬,F°0>ST$[?ṘȦŀẎcFẈṃijȯÆḋ“¦ḟw2ðƊhSẏ¥ẏ5ƒẉɦ⁺Ʋ⁴Ɓ¦ÞIzƥṙḊOḊ-÷~øWḤ0ṃ’ṃ€6676ḃ4¤ị

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Python 3, 263 bytes

s="BT R\h`NUh P_k cV\ %skgV\n"
print(''.join(i if 47>ord(i)else chr(ord(i)+865)for i in s%"Y"+"c^d b_PWX^l cV\ c`^[T`M.\n"+s%""+"_^d [T QXK [Tc`KTX cV RV.\n0_' cP YkYYPZP QRPZ[L\V,\nch\ 4ZZM\h\ cP XT`K!"+"\n9PX bP\ _`mcP P\S`TXh[L\V,\nfPN`T h fPN`T :TdcT`XK!"*3))

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Use the same repetition technique that mbomb007 used, but I replaced all characters higher than 47 (all greek letters), u913~u974 with u48~u109 ,and then undo this before printing

Java 7, 320 319 300 294 293 bytes

void Z(){String a="AS Q[g_MTg O^j bU[ ",b="8OW aO[ ^_lbO O[R_SWgZK[U,\neOM_S g eOM_S 9ScbS_WJ!\n";for(char C:(a+"XjfU\nb]c a^OVW]k bU[ b_]ZS_L.\n"+a+"jfU\n^]c ZS PWJ ZSb_JSW bU QU.\n/^' bO XjXXOYO PQOYZK[U,\nbg[ 3YYL[g[ bO WS_J!\n"+b+b+b).toCharArray())System.out.print((char)(C>46?C+866:C));}

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This outputs the anthem with a trailing newline. I converted the function from returning a String to a void so that it would print the String instead of returning it and save bytes.

Will golf further in the morning Golfers don't sleep :P

Explanation (outdated)

String Z(){
  // X contains the value of the Greek Anthem
  String X="",
  // a and b contain some repeated parts of the anthem
         a="AS Q[g_MTg O^j bU[ ",
         b="8OW aO[ ^_lbO O[R_SWgZK[U,\neOM_S g eOM_S 9ScbS_WJ!\n";
  // Then we loop over every char in this string
  for(char C: (a+"XjfU\nb]c a^OVW]k bU[ b_]ZS_L.\n"+a+"jfU\n^]c ZS PWJ ZSb_JSW bU QU.\n/^' bO XjXXOYO PQOYZK[U,\nbg[ 3YYL[g[ bO WS_J!\n"+b+b+b).toCharArray())
    // Adding 866 to the char if it is greater than `.` 46
    // (we also want to preserve the punctuation)
    X+=(char)(C>46?C+866:C);
  return X;
}

To get to this reduced String, I manually checked subtracting which numbers from the code points would be the best. These values would have to lie between and ~. In order to make the detection of whether a char is punctuation (., ', !, ) or not, it would be best if all the values lied above . (46). And there shouldn't be any \s in the String because otherwise Java thinks they are escape sequences, and so I have to escape them. Finally I came up with subtracting 866 from the Greek characters.