A function that needs to return number of legal parenthesis "()" combinations code example

Example: Given an integer 'n'. Print all the possible pairs of 'n' balanced parentheses. The output strings should be printed in the sorted order considering '(' has higher value than ')'.

def generateParentheses(openBr, closeBr, n, s = []):
	if closeBr == n:
		print(''.join(s))
		return 
	
	if closeBr < openBr:
		s.append(')')
		generateParentheses(openBr, closeBr+1, n, s)
		s.pop()
	if openBr < n:
		s.append('(')
		generateParentheses(openBr+1, closeBr, n, s)
		s.pop()
	return

n = int(input())
generateParentheses(0, 0, n)