Python argparse command line flags without arguments
Adding a quick snippet to have it ready to execute:
Source: myparser.py
import argparse
parser = argparse.ArgumentParser(description="Flip a switch by setting a flag")
parser.add_argument('-w', action='store_true')
args = parser.parse_args()
print args.w
Usage:
python myparser.py -w
>> True
As you have it, the argument w
is expecting a value after -w
on the command line. If you are just looking to flip a switch by setting a variable True
or False
, have a look here (specifically store_true and store_false)
import argparse
parser = argparse.ArgumentParser()
parser.add_argument('-w', action='store_true')
where action='store_true'
implies default=False
.
Conversely, you could haveaction='store_false'
, which implies default=True
.
Your script is right. But by default is of None type. So it considers true of any other value other than None is assigned to args.argument_name variable.
I would suggest you to add a action="store_true". This would make the True/False type of flag. If used its True else False.
import argparse
parser = argparse.ArgumentParser('parser-name')
parser.add_argument("-f","--flag",action="store_true",help="just a flag argument")
usage
$ python3 script.py -f
After parsing when checked with args.f it returns true,
args = parser.parse_args()
print(args.f)
>>>true