crazy helix hackerrank solution code example

Example 1: crazy helix hackerrank solution

public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int q = in.nextInt();
        int[] arr = new int[n];
        for(int ar_i = 0; ar_i < n; ar_i++){
            arr[ar_i] = ar_i+1;
        }
        for(int ind=1;ind<=q+1;ind++){
            int a = in.nextInt();
            if(1==a){
                reverseSubArray(arr, in.nextInt()-1, in.nextInt()-1);
            }else if(2==a){
                int b = in.nextInt();
                for(int i=0;i<arr.length;i++){
                    if(arr[i]==b){
                        System.out.println("element "+ b +" is at position "+ (i+1));
                        break;
                    }
                }
            }else if(3==a){
                int b = in.nextInt();
                System.out.println("element at position " + b +  " is " + arr[b-1]);
            }
        }
    }
    
    static void reverseSubArray(int arr[], int i, int j){
        if(i>=j) return;
		for(;i<j;i++,j--){
			int temp = arr[i];
			arr[i]=arr[j];
			arr[j]=temp;
		}
    }

Example 2: crazy helix hackerrank solution

/* Enter your code here. Read input from STDIN. Print output to STDOUT */
int main()
{
int n,q,x,y,z,t;
scanf("%d %d",&n,&q);
int a[n];
for(int i=0;i<n;i++)
{
    a[i]=i+1;
}
for(int j=0;j<q;j++)
{
    scanf("%d",&x);
    if(x==1)
    {
        int temp=0;
        scanf("%d",&y);
        scanf("%d",&z);
        t=z-y+1;
        y--;
        z--;

            for(int j=0;j<t/2;j++)
            {
                 temp=a[y+j];
                a[y+j]=a[z-j];
                a[z-j]=temp;
            }

    else if(x==2)
        {
            int t=0;
           scanf("%d",&y); 
          for(int i=0;i<n;i++)
          {
              if(a[i]==y)
              {
                  t=i;
                  break;
              }
          }
          printf("element %d is at position %d\n",y,t+1);
        }
     else
        {
           scanf("%d",&y); 
            printf("element at position %d is %d \n",y,a[y-1]);
        }

}
return 0;

Example 3: crazy helix hackerrank solution

n,queries=map(int,input().split())
num=[i+1 for i in range(n)]
for i in range(queries):
    l=list(map(int,input().split()))
    if len(l)==3:
        if l[1]==1:
            num=num[:l[1]-1]+num[l[2]-1::-1]+num[l[2]:]//1
        else:
            num=num[:l[1]-1]+num[l[2]-1:l[1]-2:-1]+num[l[2]:]//1
    elif l[0]==2:
        print("element {0} is at position {1}".format(l[1],num.index(l[1])+1))//2
    else:
        print("element at position {0} is {1}".format(l[1],num[l[1]-1]))