Python create decorator preserving function arguments

AFAIK, it is possible only since Python 3.3 with the Signature object:

def identity_decorator(wrapped):
    def wrapper(*args, **kwargs):
        return wrapped(*args, **kwargs)
    wrapper.__signature__ = inspect.signature(wrapped)  # the magic is here!
    return wrapper

Then, you can do:

@identity_decorator
def foo(a):
    pass

and finally:

>>> inspect.getargspec(foo)
ArgSpec(args=['a'], varargs=None, keywords=None, defaults=None)

As suggested in comments, you can use the decorator module or you can use eval evil powers to create a lambda function with correct signature:

import inspect

def identity_decorator(wrapped):
    argspec = inspect.getargspec(wrapped)
    args = inspect.formatargspec(*argspec)

    def wrapper(*args, **kwargs):

        return wrapped(*args, **kwargs)

    func = eval('lambda %s: wrapper%s' % (args.strip('()'), args), locals())

    return func

@identity_decorator
def foo(a):
    pass

This is kinda hackish, but it preserves function arguments:

>>> inspect.getargspec(foo)
ArgSpec(args=['a'], varargs=None, keywords=None, defaults=None)