Python - Deleting the first 2 lines of a string

Remove the lines with split:

lines = """version 1.00
6992
[-4.32063, -9.1198, -106.59][0.00064, 0.99993, -0.01210][etc...]"""

lines = lines.split('\n',2)[-1]

x="""version 1.00
6992
[-4.32063, -9.1198, -106.59][0.00064, 0.99993, -0.01210][etc...]
abc
asdda"""
print "\n".join(x.split("\n")[2:])

You can simply do this.

''.join(x.splitlines(keepends=True)[2:])

splitlines produces a list of strings. If keepends=True is given, line breaks are included in the resulting list l and ''.join(l) can be used to reproduce the original string.

---

Note that splitlines works well with a number of different line boundaries such as \u2028

>>> x = 'a\u2028b\u2028c\u2028'
>>> ''.join(x.splitlines(keepends=True)[2:])
'c\u2028'

while split('\n') fails in this case:

>>> x = 'a\u2028b\u2028c\u2028'
>>> x.split('\n',2)[2]
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
IndexError: list index out of range

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Also note that splitlines and split('\n') behave differently if they are called on an empty string or a string that ends with a newline character. Compare the following examples (copied from the documentation of splitlines):

>>> "".splitlines()
[]
>>> "One line\n".splitlines()
['One line']

>>> ''.split('\n')
['']
>>> 'Two lines\n'.split('\n')
['Two lines', '']

However, if keepends=True is given, the trailing newline is preserved:

>>> "One line\n".splitlines(keepends=True)
['One line\n']

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More examples and a list of what splitlines treats as a line boundary can be found here: https://docs.python.org/3/library/stdtypes.html?highlight=split#str.splitlines

I don't know what your end character is, but what about something like

postString = inputString.split("\n",2)[2]

The end character might need to be escaped, but that is what I would start with.