Python dictionary get multiple values

There already exists a function for this:

from operator import itemgetter

my_dict = {x: x**2 for x in range(10)}

itemgetter(1, 3, 2, 5)(my_dict)
#>>> (1, 9, 4, 25)

itemgetter will return a tuple if more than one argument is passed. To pass a list to itemgetter, use

itemgetter(*wanted_keys)(my_dict)

Keep in mind that itemgetter does not wrap its output in a tuple when only one key is requested, and does not support zero keys being requested.

Use a for loop:

keys = ['firstKey', 'secondKey', 'thirdKey']
for key in keys:
    myDictionary.get(key)

or a list comprehension:

[myDictionary.get(key) for key in keys]

No-one has mentioned the map function, which allows a function to operate element-wise on a list:

mydictionary = {'a': 'apple', 'b': 'bear', 'c': 'castle'}
keys = ['b', 'c']

values = list( map(mydictionary.get, keys) )

# values = ['bear', 'castle']