excelvba is specific bit set in long integer code example

Example 1: vba low word from Long Integer

'If n is a 4-byte Long Integer, the Low (Left) Word is:
If n And &H8000& Then
  	LoWord = n Or &HFFFF0000
Else
    LoWord = n And &HFFFF&
End If

'If n is a 4-byte Long Integer, the High (Right) Word is:
HiWord = (n And &HFFFF0000) \ &H10000

Example 2: excel vba long to bits

Function LongToBits$(ByVal n&)
    Dim i&
    LongToBits = "00000000000000000000000000000000"
    If n And &H80000000 Then
        Mid$(LongToBits, 1, 1) = "1"
        n = n And Not &H80000000
    End If
    For i = 32 To 2 Step -1
        If n And 1 Then Mid$(LongToBits, i, 1) = "1"
        n = n \ 2
    Next
End Function

'------------------------------------------------------------------------------

MsgBox ByteToBits(0)			'<--displays: 00000000000000000000000000000000
MsgBox LongToBits(293781237)	'<--displays: 00010001100000101011111011110101
MsgBox ByteToBits(-1)			'<--displays: 11111111111111111111111111111111

Example 3: excel vba is bit set long

'Extremely fast VBA function to test if a specified bit is set 
'within a 32-bit Long integer.

'Bits are numbered from 0 to 31, so the first (least significant) bit
'is bit 0.

'Note: we do not inspect bit 31, the sign bit.
'Note: any number of bits can be specified in one call.


Function LongBitIsSet(theLong&, bit As Byte) As Boolean
    Static i&, b&()
    If (Not Not b) = 0 Then
        ReDim b(0 To 30)
        For i = 0 To 30
            b(i) = 2 ^ i
        Next
    End If
    If bit < 31 Then LongBitIsSet = theLong And b(bit)
End Function


'------------------------------------------------------------------
MsgBox LongBitIsSet(255, 7)             '<--displays: True
MsgBox LongBitIsSet(230, 0)             '<--displays: False
MsgBox LongBitIsSet(16384, 14)          '<--displays: True
MsgBox LongBitIsSet(-16383, 0)          '<--displays: True
MsgBox LongBitIsSet(&H7FFFFFFF, 0)      '<--displays: True