Python: Find index of minimum item in list of floats

You're effectively scanning the list once to find the min value, then scanning it again to find the index, you can do both in one go:

from operator import itemgetter
min(enumerate(a), key=itemgetter(1))[0] 

Use of the argmin method for numpy arrays.

import numpy as np
np.argmin(myList)

However, it is not the fastest method: it is 3 times slower than OP's answer on my computer. It may be the most concise one though.

I would use:

val, idx = min((val, idx) for (idx, val) in enumerate(my_list))

Then val will be the minimum value and idx will be its index.