how to order a dictionary python code example

Example 1: python sort dictionary alphabetically by key

sortednames=sorted(dictUsers.keys(), key=lambda x:x.lower())

Example 2: python dict sort by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Example 3: sort the dictionary in python

d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)

Example 4: python sort dictionary by key

In [1]: import collections

In [2]: d = {2:3, 1:89, 4:5, 3:0}

In [3]: od = collections.OrderedDict(sorted(d.items()))

In [4]: od
Out[4]: OrderedDict([(1, 89), (2, 3), (3, 0), (4, 5)])

Example 5: sort a dictionary

from operator import itemgetter
new_dict = sorted(data.items(), key=itemgetter(1))

Example 6: sort dictionary by values

from collections import OrderedDict
dd = OrderedDict(sorted(d.items(), key=lambda x: x[1]))
print(dd)