python httplib/urllib get filename

Does not make much sense what you are asking. The only thing that you have is the URL. Either extract the last part from the URL or you may check the HTTP response for something like

content-disposition: attachment;filename="foo.bar"

This header can be set by the server to indicate that the filename is foo.bar. This is usually used for file downloads or something similar.

Use urllib.request.Request:

import urllib

req = urllib.request.Request(url, method='HEAD')
r = urllib.request.urlopen(req)
print(r.info().get_filename())

Example :

In[1]: urllib.request.urlopen(urllib.request.Request('https://httpbin.org/response-headers?content-disposition=%20attachment%3Bfilename%3D%22example.csv%22', method='HEAD')).info().get_filename()
Out[1]: 'example.csv'

To get filename from response http headers:

import cgi

response = urllib2.urlopen(URL)
_, params = cgi.parse_header(response.headers.get('Content-Disposition', ''))
filename = params['filename']

To get filename from the URL:

import posixpath
import urlparse 

path = urlparse.urlsplit(URL).path
filename = posixpath.basename(path)