if a operator is encountered while scanning the expression what is next course of action code example
Example: python postfix conversion
"""
Author : ITVoyagers (itvoyagers.in)
Date :31st October 2019
Description : Program to show use of stack in infix to postfix conversion using python.
"""
class infix_to_postfix:
precedence={'^':5,'*':4,'/':4,'+':3,'-':3,'(':2,')':1}
def __init__(self):
self.items=[]
self.size=-1
def push(self,value):
self.items.append(value)
self.size+=1
def pop(self):
if self.isempty():
return 0
else:
self.size-=1
return self.items.pop()
def isempty(self):
if(self.size==-1):
return True
else:
return False
def seek(self):
if self.isempty():
return false
else:
return self.items[self.size]
def isOperand(self,i):
if i in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ':
return True
else:
return False
def infixtopostfix (self,expr):
postfix=""
print('postfix expression after every iteration is:')
for i in expr:
if(len(expr)%2==0):
print("Incorrect infix expr")
return False
elif(self.isOperand(i)):
postfix +=i
elif(i in '+-*/^'):
while(len(self.items)and self.precedence[i]<=self.precedence[self.seek()]):
postfix+=self.pop()
self.push(i)
elif i is '(':
self.push(i)
elif i is ')':
o=self.pop()
while o!='(':
postfix +=o
o=self.pop()
print(postfix)
while len(self.items):
if(self.seek()=='('):
self.pop()
else:
postfix+=self.pop()
return postfix
s=infix_to_postfix()
expr=input('enter the expression ')
result=s.infixtopostfix(expr)
if (result!=False):
print("the postfix expr of :",expr,"is",result)