max of dictionary python code example

Example 1: python find the key with max value

a_dictionary = {"a": 1, "b": 2, "c": 3}

# get key with max value
max_key = max(a_dictionary, key=a_dictionary.get)

print(max_key)

Example 2: max of a dict

dic={0: 1.4984074067880424, 1: 1.0984074067880423, 2: 1.8984074067880425, 3: 2.2984074067880425, 4: 2.2984074067880425}
max_value = max(dic.values())  # maximum value
max_keys = [k for k, v in dic.items() if v == max_value] # getting all keys containing the `maximum`

print(max_value, max_keys)

Example 3: find the max value in dictionary python

my_dict = {'a': 5, 'b': 10, 'c': 6, 'd': 12, 'e': 7}
max(my_dict, key=my_dict.get) # returns 'd'

Example 4: python get min max value from a dictionary

d = {'A': 4,'B':10}
min_v = min(zip(d.values(), d.keys()))
# min_v is (4,'A')

max_v = max(zip(d.values(), d.keys()))
# max_v is (10,'B')

Example 5: python max key dictionary key getter

from operator import itemgetter

items = [
    {'a': 1, 'b': 99},
    {'a': 2, 'b': 88},
    {'a': 3, 'b': 77},
]

print(max(items, key=itemgetter('a')))
print(max(items, key=itemgetter('b')))

Example 6: get max n values in dict py

import heapq
from operator import itemgetter

n = 3

items = {'a': 7, 'b': 12, 'c': 9, 'd': 0, 'e': 24, 'f': 10, 'g': 24}

topitems = heapq.nlargest(n, items.items(), key=itemgetter(1))  # Use .iteritems() on Py2
topitemsasdict = dict(topitems)