mongodb group by code example

Example 1: mongodb group by having

#It's the equivalent of the following SQL instruction:
# SELECT COUNT(*) FROM Table
# GROUP BY your_field
# HAVING COUNT(*) > N
query = db.collection.aggregate([

    { 
      "$group": { "_id": "$your_field", #GROUP BY your_field
    			"count": {"$sum":1} }   #COUNT(*)
    },
    
    { "$match": { "count": { "$gt": N } } } #HAVING COUNT(*) > N
])

Example 2: mongodb aggregate group

#equivalent of the following SQL instruction:
# SELECT COUNT(*) FROM Table
# GROUP BY your_field
query = db.collection.aggregate([
    { 
        "$group": {
            "_id": "$your_field", #GROUP BY your_field
            "total": {"$sum":1}   #COUNT(*)
        }
    }
])

Example 3: group by mongo

db.sales.aggregate([
  // First Stage
  {
    $match : { "date": { $gte: new ISODate("2014-01-01"), $lt: new ISODate("2015-01-01") } }
  },
  // Second Stage
  {
    $group : {
       _id : { $dateToString: { format: "%Y-%m-%d", date: "$date" } },
       totalSaleAmount: { $sum: { $multiply: [ "$price", "$quantity" ] } },
       averageQuantity: { $avg: "$quantity" },
       count: { $sum: 1 }
    }
  },
  // Third Stage
  {
    $sort : { totalSaleAmount: -1 }
  }
 ])

Example 4: group by mongo

db.books.aggregate([
   // First Stage
   {
     $group : { _id : "$author", books: { $push: "$$ROOT" } }
   },
   // Second Stage
   {
     $addFields:
       {
         totalCopies : { $sum: "$books.copies" }
       }
   }
 ])