python operator precedence of in and comparison

It has nothing to do with precedence. In Python relational operators chain, and containment is considered a relational operator. Therefore:

'1' in '11' == True

is the same as:

('1' in '11') and ('11' == True)

which is false since True is not equal to "11".

The Python manual says in and == are of equal precedence. Thus, they're evaluated from left to right by default, but there's also chaining to consider. The expression you put above ('1' in '11' == True) is actually being evaluated as...

('1' in '11') and ('11' == True)

which of course is False. If you don't know what chaining is, it's what allows you to do something like...

if 0 < a < 1:

in Python, and have that mean what you expect ("a is greater than 0 but less than 1").

Chaining allows you to write x < y < z, and mean x < y and y < z. Look at this interaction:

>>> (False == True) == False
True
>>> False == (True == False)
True
>>> False == True == False
False
>>>

So in your example, '1' in '11' == True is equivalent to ('1' in '11') and ('11' == True)