Python & Pandas - Group by day and count for each day
Hey I found easy way to do this with resample.
# Set the date column as index column.
df = df.set_index('your_date_column')
# Make counts
df_counts = df.your_date_column.resample('D').count()
Although your column name is long and contains spaces, which makes me a little cringy. I would use dashes instead of spaces.
To make sure your columns in in date format.
df['date & time of connection']=pd.to_datetime(df['date & time of connection'])
Then you can group the data by date and do a count:
df.groupby(by=df['date & time of connection'].dt.date).count()
Out[10]:
date & time of connection
date & time of connection
2017-06-19 3
2017-06-20 2
2017-06-21 5
2017-06-22 3
2017-06-23 6
You can use dt.floor
for convert to date
s and then value_counts
or groupby
with size
:
df = (pd.to_datetime(df['date & time of connection'])
.dt.floor('d')
.value_counts()
.rename_axis('date')
.reset_index(name='count'))
print (df)
date count
0 2017-06-23 6
1 2017-06-21 5
2 2017-06-19 3
3 2017-06-22 3
4 2017-06-20 2
Or:
s = pd.to_datetime(df['date & time of connection'])
df = s.groupby(s.dt.floor('d')).size().reset_index(name='count')
print (df)
date & time of connection count
0 2017-06-19 3
1 2017-06-20 2
2 2017-06-21 5
3 2017-06-22 3
4 2017-06-23 6
Timings:
np.random.seed(1542)
N = 220000
a = np.unique(np.random.randint(N, size=int(N/2)))
df = pd.DataFrame(pd.date_range('2000-01-01', freq='37T', periods=N)).drop(a)
df.columns = ['date & time of connection']
df['date & time of connection'] = df['date & time of connection'].dt.strftime('%d/%m/%Y %H:%M:%S')
print (df.head())
In [193]: %%timeit
...: df['date & time of connection']=pd.to_datetime(df['date & time of connection'])
...: df1 = df.groupby(by=df['date & time of connection'].dt.date).count()
...:
539 ms ± 45.9 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)
In [194]: %%timeit
...: df1 = (pd.to_datetime(df['date & time of connection'])
...: .dt.floor('d')
...: .value_counts()
...: .rename_axis('date')
...: .reset_index(name='count'))
...:
12.4 ms ± 350 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
In [195]: %%timeit
...: s = pd.to_datetime(df['date & time of connection'])
...: df2 = s.groupby(s.dt.floor('d')).size().reset_index(name='count')
...:
17.7 ms ± 140 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)