remove duplicates from sorted array solution code example

Example 1: python remove duplicates from list

mylist = ["a", "b", "b", "c", "a"]
mylist = sorted(set(mylist))
print(mylist)

Example 2: remove duplicates from array

let chars = ['A', 'B', 'A', 'C', 'B'];
let uniqueChars = [...new Set(chars)];

console.log(uniqueChars);

output:
[ 'A', 'B', 'C' ]

Example 3: remove duplicates from sorted array

// Java
public int removeDuplicates(int[] nums) {
    if (nums.length == 0) return 0;
    int i = 0;
    for (int j = 1; j < nums.length; j++) {
        if (nums[j] != nums[i]) {
            i++;
            nums[i] = nums[j];
        }
    }
    return i + 1;
}

Example 4: remove duplicates in sorted array python

j = 0

// traverse elements of arr
for i=0 to n-2
    // if ith element is not equal to (i+1)th element of arr, then store ith value in arr[j]
    if arr[i] != arr[i+1]
        arr[j] = arr[i]
        j += 1

// store last value of arr in temp
arr[j] = arr[n-1]
j += 1

// print first j elements of array arr
for i=0 to j-1 
    print arr[i]

Example 5: remove duplicates from sorted array

def remove_duplicate(nums: [int]) -> int:
  nums[:] = sorted(set(nums))
  return len(nums)

Example 6: remove duplicates from sorted array

def remove_duplicates(nums: [int]) -> int:
    cnt = 1
    for index in range(len(nums) - 1):
        if nums[index] != nums[index + 1]:
            nums[cnt] = nums[index + 1]
            cnt += 1
    print(cnt)