python requests: how to check for "200 OK"
Just check the response attribute resp.ok
. It is True
for all 2xx responses, but False
for 4xx and 5xx. However, the pythonic way to check for success would be to optionally raise an exception with Response.raise_for_status()
:
try:
resp = requests.get(url)
resp.raise_for_status()
except requests.exceptions.HTTPError as err:
print(err)
EAFP: It’s Easier to Ask for Forgiveness than Permission: You should just do what you expect to work and if an exception might be thrown from the operation then catch it and deal with that fact.
According to the docs, there's a status_code property on the response-object. So you can do the following:
if resp.status_code == 200:
print ('OK!')
else:
print ('Boo!')
EDIT:
As others have pointed out, a simpler check would be
if resp.ok:
print ('OK!')
else:
print ('Boo!')
if you want to consider all 2xx
response codes and not 200
explicitly.
You may also want to check Peter's answer for a more python-like way to do this.
Much simpler check would be
if resp.ok :
print ('OK!')
else:
print ('Boo!')