Python select random date in current year

import datetime, time
import random

def year_start(year):
    return time.mktime(datetime.date(year, 1, 1).timetuple())

def rand_day(year):
    stamp = random.randrange(year_start(year), year_start(year + 1))
    return datetime.date.fromtimestamp(stamp)

Edit: Ordinal dates as used in Michael Dunns answer are way better to use then timestamps! One might want to combine the use of ordinals with this though.

It's much simpler to use ordinal dates (according to which today's date is 734158):

from datetime import date
import random

start_date = date.today().replace(day=1, month=1).toordinal()
end_date = date.today().toordinal()
random_day = date.fromordinal(random.randint(start_date, end_date))

This will fail for dates before 1AD.

Not directly, but you could add a random number of days to January 1st. I guess the following should work for the Gregorian calendar:

from datetime import date, timedelta
import random
import calendar

# Assuming you want a random day of the current year
firstJan = date.today().replace(day=1, month=1) 

randomDay = firstJan + timedelta(days = random.randint(0, 365 if calendar.isleap(firstJan.year) else 364))