tic tac toe game in python with source code code example
Example: tic tac toe python easy
def tic_tac_toe():
board = [1, 2, 3, 4, 5, 6, 7, 8, 9]
end = False
win_commbinations = ((0, 1, 2), (3, 4, 5), (6, 7, 8), (0, 3, 6), (1, 4, 7), (2, 5, 8), (0, 4, 8), (2, 4, 6))
def draw():
print(board[0], board[1], board[2])
print(board[3], board[4], board[5])
print(board[6], board[7], board[8])
print()
def p1():
n = choose_number()
if board[n] == "X" or board[n] == "O":
print("\nYou can't go there. Try again")
p1()
else:
board[n] = "X"
def p2():
n = choose_number()
if board[n] == "X" or board[n] == "O":
print("\nYou can't go there. Try again")
p2()
else:
board[n] = "O"
def choose_number():
while True:
while True:
a = input()
try:
a = int(a)
a -= 1
if a in range(0, 9):
return a
else:
print("\nThat's not on the board. Try again")
continue
except ValueError:
print("\nThat's not a number. Try again")
continue
def check_board():
count = 0
for a in win_commbinations:
if board[a[0]] == board[a[1]] == board[a[2]] == "X":
print("Player 1 Wins!\n")
print("Congratulations!\n")
return True
if board[a[0]] == board[a[1]] == board[a[2]] == "O":
print("Player 2 Wins!\n")
print("Congratulations!\n")
return True
for a in range(9):
if board[a] == "X" or board[a] == "O":
count += 1
if count == 9:
print("The game ends in a Tie\n")
return True
while not end:
draw()
end = check_board()
if end == True:
break
print("Player 1 choose where to place a cross")
p1()
print()
draw()
end = check_board()
if end == True:
break
print("Player 2 choose where to place a nought")
p2()
print()
if input("Play again (y/n)\n") == "y":
print()
tic_tac_toe()
tic_tac_toe()