Random background image on refresh

<div ="#background"></div>

should be

<div id="background"></div>

(Or was that just a typo?)


You must have comma separators between the array values when you define your array.

You should also have two separate script elements, one for including jquery and the other for your code.

The content of a script tag with a src-attribute should be ignored by most browsers.

<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js" type="text/javascript" ></script>

<script type="text/javascript">
 var images = ['OUT01ari.jpg', 'OUT02adobe.jpg', 'OUT03alife.jpg', 'OUT04chinup.jpg', 'OUT05datenightwinecologne.jpg', 'OUT06officechair.jpg', 'OUT07printer.jpg', 'OUT08whitewall.jpg', 'OUT09umbrella.jpg', 'OUT10converse.jpg', 'OUT11wardrobebar.jpg'];
 $('#background').css({'background-image': 'url(images/' + images[Math.floor(Math.random() * images.length)] + ')'});
</script>

W3C 4.3 Scripting HTML5 says:

If there is a src attribute, the element must be either empty or contain only script documentation that also matches script content restrictions.

And the same is true for earlier versions I believe.

Edit:

If you are working on the local file system , make sure to change the URL to jQuery to http:// instead of just //.

Also, make sure your script is executed when the #background element exists by calling in on document ready.

This example should work even locally:

<html>
 <head>
  <style type="text/css">
   #background { 
    position:fixed; left: 0px; 
    top: 0px; background-size:100%;  
     width:100%; height:100%; 
     -webkit-user-select: none; -khtml-user-select: none; 
     -moz-user-select: none; -o-user-select: none; user-select: none; 
      z-index:9990; 
    }
  </style>
  <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js" type="text/javascript" ></script>
  <script type="text/javascript">
   $(function() {
    var images = ['OUT01ari.jpg', 'OUT02adobe.jpg', 'OUT03alife.jpg', 'OUT04chinup.jpg', 'OUT05datenightwinecologne.jpg', 'OUT06officechair.jpg', 'OUT07printer.jpg', 'OUT08whitewall.jpg', 'OUT09umbrella.jpg', 'OUT10converse.jpg', 'OUT11wardrobebar.jpg'];
    $('#background').css({'background-image': 'url(images/' + images[Math.floor(Math.random() * images.length)] + ')'});
   });
  </script>
 </head>
 <body>
  <div id="background"></div>
  <div class="container">
  </div>
 </body>
</html>

Tags:

Image

Jquery

Web

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