Read last line from file

You're looking for the fseek function. There are working examples of how to read the last line of a file in the comments section there.

This should work:

$line = '';

$f = fopen('data.txt', 'r');
$cursor = -1;

fseek($f, $cursor, SEEK_END);
$char = fgetc($f);

/**
 * Trim trailing newline chars of the file
 */
while ($char === "\n" || $char === "\r") {
    fseek($f, $cursor--, SEEK_END);
    $char = fgetc($f);
}

/**
 * Read until the start of file or first newline char
 */
while ($char !== false && $char !== "\n" && $char !== "\r") {
    /**
     * Prepend the new char
     */
    $line = $char . $line;
    fseek($f, $cursor--, SEEK_END);
    $char = fgetc($f);
}

fclose($f);

echo $line;

Note that this solution will repeat the last character of the line unless your file ends in a newline. If your file does not end in a newline, you can change both instances of $cursor-- to --$cursor.

Use fseek. You seek to the last position and seek it backward (use ftell to tell the current position) until you find a "\n".

$fp = fopen(".....");
fseek($fp, -1, SEEK_END); 
$pos = ftell($fp);
$LastLine = "";
// Loop backword util "\n" is found.
while((($C = fgetc($fp)) != "\n") && ($pos > 0)) {
    $LastLine = $C.$LastLine;
    fseek($fp, $pos--);
}
fclose($fp);

NOTE: I've not tested. You may need some adjustment.

UPDATE: Thanks Syntax Error for pointing out about empty file.

:-D

UPDATE2: Fixxed another Syntax Error, missing semicolon at $LastLine = ""