Read numbers from a text file in C#

Brannon's answer explains how to read binary data. If you want to read text data, you should be reading strings and then parsing them - for which there are built-in methods, of course.

For example, to read a file with data:

10
10.5
hello

You might use:

using (TextReader reader = File.OpenText("test.txt"))
{
    int x = int.Parse(reader.ReadLine());
    double y = double.Parse(reader.ReadLine());
    string z = reader.ReadLine();
}

Note that this has no error handling. In particular, it will throw an exception if the file doesn't exist, the first two lines have inappropriate data, or there are less than two lines. It will leave a value of null in z if the file only has two lines.

For a more robust solution which can fail more gracefully, you would want to check whether reader.ReadLine() returned null (indicating the end of the file) and use int.TryParse and double.TryParse instead of the Parse methods.

That's assuming there's a line separator between values. If you actually want to read a string like this:

10 10.5 hello

then the code would be very similar:

using (TextReader reader = File.OpenText("test.txt"))
{
    string text = reader.ReadLine();
    string[] bits = text.Split(' ');
    int x = int.Parse(bits[0]);
    double y = double.Parse(bits[1]);
    string z = bits[2];
}

Again, you'd want to perform appropriate error detection and handling. Note that if the file really just consisted of a single line, you may want to use File.ReadAllText instead, to make it slightly simpler. There's also File.ReadAllLines which reads the whole file into a string array of lines.

EDIT: If you need to split by any whitespace, then you'd probably be best off reading the whole file with File.ReadAllText and then using a regular expression to split it. At that point I do wonder how you represent a string containing a space.

In my experience you generally know more about the format than this - whether there will be a line separator, or multiple values in the same line separated by spaces, etc.

I'd also add that mixed binary/text formats are generally unpleasant to deal with. Simple and efficient text handling tends to read into a buffer, which becomes problematic if there's binary data as well. If you need a text section in a binary file, it's generally best to include a length prefix so that just that piece of data can be decoded.

using (FileStream fs = File.OpenRead("file.txt"))
{
    BinaryReader reader = new BinaryReader(fs);

    int intVal = reader.ReadInt32();
    float floatVal = reader.ReadSingle();
    string stringVal = reader.ReadString();
}

Not exactly the answer to your question, but just an idea to consider if you are new to C#: If you are using a custom text file to read some configuration parameters, you might want to check XML serialization topics in .NET.

XML serialization provides a simple way to write and read XML formatted files. For example, if you have a configuration class like this:

public class Configuration
{
   public int intVal { get; set; }
   public float floatVal { get; set; }
   public string stringVal { get; set; }
}

you can simply save it and load it using the XmlSerializer class:

public void Save(Configuration config, string fileName)
{
   XmlSerializer xml = new XmlSerializer(typeof(Configuration));
   using (StreamWriter sw = new StreamWriter(fileName))
   {
       xml.Serialize(sw, config);
   }
}

public Configuration Load(string fileName)
{
   XmlSerializer xml = new XmlSerializer(typeof(Configuration));
   using (StreamReader sr = new StreamReader(fileName))
   {
       return (Configuration)xml.Deserialize(sr);
   }
}

Save method as defined above will create a file with the following contents:

<Configuration>
    <intVal>0</intVal>
    <floatVal>0.0</floatVal>
    <stringVal></stringVal>
</Configuration>

Good thing about this approach is that you don't need to change the Save and Load methods if your Configuration class changes.