Regex: Get Filename Without Extension in One Shot?

Try this:

(.+?)(\.[^.]*$|$)

This will:

• Capture filenames that start with a dot (e.g. .logs is a file named .logs, not a file extension), which is common in Unix.
• Gets everything but the last dot: foo.bar.jpeg gets you foo.bar.
• Handles files with no dot: secret-letter gets you secret-letter.

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Note: as commenter j_random_hacker suggested, this performs as advertised, but you might want to precede things with an anchor for readability purposes.

Everything followed by a dot followed by one or more characters that's not a dot, followed by the end-of-string:

(.+?)\.[^\.]+$

The everything-before-the-last-dot is grouped for easy retrieval.

If you aren't 100% sure every file will have an extension, try:

(.+?)(\.[^\.]+$|$)

^(.*)\\(.*)(\..*)$

1. Gets the Path without the last \
2. The file without extension
3. The the extension with a .

Examples:

c:\1\2\3\Books.accdb
(c:\1\2\3)(Books)(.accdb)

Does not support multiple . in file name Does support . in file path

how about 2 captures one for the end and one for the filename.

eg.

(.+?)(?:\.[^\.]*$|$)